x^2+12x+40=5

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Solution for x^2+12x+40=5 equation:


Simplifying
x2 + 12x + 40 = 5

Reorder the terms:
40 + 12x + x2 = 5

Solving
40 + 12x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
40 + -5 + 12x + x2 = 5 + -5

Combine like terms: 40 + -5 = 35
35 + 12x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
35 + 12x + x2 = 0

Factor a trinomial.
(7 + x)(5 + x) = 0

Subproblem 1

Set the factor '(7 + x)' equal to zero and attempt to solve: Simplifying 7 + x = 0 Solving 7 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + x = 0 + -7 x = 0 + -7 Combine like terms: 0 + -7 = -7 x = -7 Simplifying x = -7

Subproblem 2

Set the factor '(5 + x)' equal to zero and attempt to solve: Simplifying 5 + x = 0 Solving 5 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + x = 0 + -5 x = 0 + -5 Combine like terms: 0 + -5 = -5 x = -5 Simplifying x = -5

Solution

x = {-7, -5}

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